Keys for yesterdays content: 

Solutions:

1. Required length = H.C.F of 700 cm, 385 cm and 1295 cm =35 cm.

2. Required measurement = (H.C.F. of  496,403,713)litres = 31 litres.

3. Required number of students = H.C.F. of 1001 and 910 = 91.

4. Largest size of the tile = H.C.F. of 378 cm and 525 cm = 21 cm.

5. Required number =H.C.F. of (91 – 43), (183 – 91) and (183 – 43)

                                   = H.C.F. of 48,92 and 140 = 4.

6. N = H.C.F. of (4665 – 1305), (6905 – 4665) and 6905 – 1305)

        = H.C.F. of 3360,2240 and 5600 = 1120.

Sum of digits in N = (1 + 1 + 2 + 0) = 4.

7. Required number = H.C.F. of (1356 – 12),(1868 – 12) and (2764 – 12)

                                   = H.C.F. of 1344, 1856 and 2752 = 64.

8. Required number = H.C.F. of (1657 – 6) and (2037 -5)

                                   = H.C.F. of 1651 and 2032 = 127.

9. L.C.M. of 8,16,40 and 80 = 80.

    7     70      13      65     31       62

   __ =  __ ;  ___ = ___ ;  ___ =  ___  .

   8      80      16      80     40       80

            70     63      65     62         7      63       13       31

Since, ___> ___> ___ >___ ,so ___ >___ > ___ >  ___

           80      80     80      80         8      80      16        40

So, 7/8 is the largest

10.  L.C.M. of 12, 18, 21, 30                                   

                       = 2 x 3 x 2 x 3 x 7 x 5 = 1260

\ Required number = (1260 ¸ 2 ) = 630.